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Ionisation
The estimation of the ionisation energy from the hydrogen analogy in the
previous chapter was illustrative, but not very accurate. We can determine
the ionisation energy of dopants by the temperature dependence of the carrier
density. Assume a n-type semiconductor with a donor density ND.
The density of occupied donor states nD is given by the
an expression very similar to the Fermi-Dirac distribution:
Here, ED is the "depth" of the donor, and β
a factor for describing how many equivalent band minima are available at
the conduction band minimum (also called band degeneracy). At low
temperatures all donor electrons are bound to their donor atoms, they are
"frozen". The Fermi level is at its intrinsic position. As we increase
the temperature, more and more donors are ionised. The increased electron
density also raises the Fermi level which in turn controls how many donors
are ionised and so forth. Charge neutrality requires that the number of
excited and bound electrons add up to the number of donors:
n + nD = ND
For the calculation of the actual electron density we combine the equation
of charge neutrality and the relation between electron density and Fermi
level of the previous section. Then, we eliminate nD
as well as the explicite dependence on the Fermi level. This yields a second
order equation for the dependence of the electron densitiy n on
the temperature T. A graphical representation in Arrhenius form is shown
below, assuming a bandgap of 1.2 eV, a donor depth of 100 meV, and a donor
density of 1015 1/cm3.
In the useful range between 200 and 500 K all donors are ionised, we can
assume n = ND. For lower temperatures the electron
density freezes out with an activation energy of half the donor depth.
Thus, Hall measurements at different temperatures can be used to find the
activation energy for donor ionisation. For higher temperatures the electron
density is dominated by the intrinsic carrier density n=sqrt(ni2).
Compensation
In less ideal semiconductors both, donors and acceptors, will be present
simultaneously. With a donor density ND and an
acceptor density NA we observe only a net
dopant concentration in the equation for charge neutrality.
n + nD = ND- NA
The degree of compensation K is defined as the ratio of NA
and ND. The activation energy plot becomes a little more
difficult. For moderate compensation there are two regions with different
slope as shown in the figure. More often compensation levels of 90 or
99% percent are found which substantially complicates the interpretation.

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